std::find, std::find_if, std::find_if_not
|   Defined in header  
<algorithm>
  | 
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|   template< class InputIt, class T > 
InputIt find( InputIt first, InputIt last, const T& value );  | 
(1) | |
|   template< class InputIt, class UnaryPredicate > 
InputIt find_if( InputIt first, InputIt last,   | 
(2) | |
|   template< class InputIt, class UnaryPredicate > 
InputIt find_if_not( InputIt first, InputIt last,   | 
(3) | (since C++11) | 
These functions find the first element in the range [first, last) that satisfies specific criteria:
1. find searches for an element equal to value
2. find_if searches for an element for which predicate p returns true
3. find_if_not searches for element for which predicate q returns false
Contents | 
[edit] Parameters
| first, last | - | the range of elements to examine | |||||||||
| value | - | value to compare the elements to | |||||||||
| p | - |   unary predicate which returns true  for the required element.  The signature of the predicate function should be equivalent to the following: 
 The signature does not need to have const &, but the function must not modify the objects passed to it.  | 
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| q | - |   unary predicate which returns false  for the required element.  The signature of the predicate function should be equivalent to the following: 
 The signature does not need to have const &, but the function must not modify the objects passed to it.  | 
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| Type requirements | |||||||||||
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InputIt must meet the requirements of InputIterator.
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UnaryPredicate must meet the requirements of Predicate.
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[edit] Return value
Iterator to the first element satisfying the condition or last if no such element is found.
[edit] Complexity
At most last - first applications of the predicate
[edit] Possible implementation
| First version | 
|---|
template<class InputIt, class T> InputIt find(InputIt first, InputIt last, const T& value) { for (; first != last; ++first) { if (*first == value) { return first; } } return last; }  | 
| Second version | 
template<class InputIt, class UnaryPredicate> InputIt find_if(InputIt first, InputIt last, UnaryPredicate p) { for (; first != last; ++first) { if (p(*first)) { return first; } } return last; }  | 
| Third version | 
template<class InputIt, class UnaryPredicate> InputIt find_if_not(InputIt first, InputIt last, UnaryPredicate q) { for (; first != last; ++first) { if (!q(*first)) { return first; } } return last; }  | 
If you do not have C++11, an equivalent to std::find_if_not is to use std::find_if with the negated predicate.
template<class InputIt, class UnaryPredicate> InputIt find_if_not(InputIt first, InputIt last, UnaryPredicate q) { return std::find_if(first, last, std::not1(q)); }  | 
[edit] Example
The following example finds an integer in a vector of integers.
#include <iostream> #include <algorithm> #include <vector> int main() { int n1 = 3; int n2 = 5; std::vector<int> v{0, 1, 2, 3, 4}; auto result1 = std::find(v.begin(), v.end(), n1); auto result2 = std::find(v.begin(), v.end(), n2); if (result1 != v.end()) { std::cout << "v contains: " << n1 << '\n'; } else { std::cout << "v does not contain: " << n1 << '\n'; } if (result2 != v.end()) { std::cout << "v contains: " << n2 << '\n'; } else { std::cout << "v does not contain: " << n2 << '\n'; } }
Output:
v contains: 3 v does not contain: 5
[edit] See also
|    finds two identical (or some other relationship) items adjacent to each other   (function template)  | 
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|    finds the last sequence of elements in a certain range   (function template)  | 
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|    searches for any one of a set of elements   (function template)  | 
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|    finds the first position where two ranges differ   (function template)  | 
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|    searches for a range of elements   (function template)  | 
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